What are the solutions to the equation 8x^2+7x=-2 ?

The solutions to the equation 8x^2+7x=-2 are x=-7/16+i(sqrt(15))/(16),x=-7/16-i(sqrt(15))/(16)

Find the zeros of 8x^2+7x=-2

The zeros of 8x^2+7x=-2 are x=-7/16+i(sqrt(15))/(16),x=-7/16-i(sqrt(15))/(16)

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8 x^{2} + 7 x = - 2

x = - \frac{7}{16} + i \frac{15}{16}, x = - \frac{7}{16} - i \frac{15}{16}

Solution steps

8 x^{2} + 7 x = - 2

Move

2

to the left side

8 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

Simplify

7^{2} - 4 \cdot 8 \cdot 2 : 15 i

x_{1, 2} = \frac{- 7 \pm 15 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 7 + 15 i}{2 \cdot 8}, x_{2} = \frac{- 7 - 15 i}{2 \cdot 8}

x = \frac{- 7 + 15 i}{2 \cdot 8} : - \frac{7}{16} + i \frac{15}{16}

x = \frac{- 7 - 15 i}{2 \cdot 8} : - \frac{7}{16} - i \frac{15}{16}

The solutions to the quadratic equation are:

x = - \frac{7}{16} + i \frac{15}{16}, x = - \frac{7}{16} - i \frac{15}{16}

(x - 9) (x - 5) = 0

- 6 x^{2} + 23 x = 20

x^{2} + 3 - 10 = 0

(x) = x^{2}

x^{2} - 4 x - 8 = 4

What are the solutions to the equation 8x^2+7x=-2 ?
The solutions to the equation 8x^2+7x=-2 are x=-7/16+i(sqrt(15))/(16),x=-7/16-i(sqrt(15))/(16)
Find the zeros of 8x^2+7x=-2
The zeros of 8x^2+7x=-2 are x=-7/16+i(sqrt(15))/(16),x=-7/16-i(sqrt(15))/(16)