What are the solutions to the equation r^2-2r=8 ?

The solutions to the equation r^2-2r=8 are r=4,r=-2

Find the zeros of r^2-2r=8

The zeros of r^2-2r=8 are r=4,r=-2

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r^{2} - 2 r = 8

r = 4, r = - 2

Solution steps

r^{2} - 2 r = 8

Move

8

to the left side

r^{2} - 2 r - 8 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

r_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, r_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

r = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

r = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

r = 4, r = - 2

- 3 x^{2} - 6 x - 3 = 0

100 - 0.04 x = 0.000006 x^{2} - 0.02 x + 25

x^{2} = 10 x - 21

3 x^{2} - 7 x - 1

n^{2} - 2 n - 15 = 0

What are the solutions to the equation r^2-2r=8 ?
The solutions to the equation r^2-2r=8 are r=4,r=-2
Find the zeros of r^2-2r=8
The zeros of r^2-2r=8 are r=4,r=-2