What are the solutions to the equation 2x^2-9x+18=0 ?

The solutions to the equation 2x^2-9x+18=0 are x= 9/4+i(3sqrt(7))/4 ,x= 9/4-i(3sqrt(7))/4

Find the zeros of 2x^2-9x+18=0

The zeros of 2x^2-9x+18=0 are x= 9/4+i(3sqrt(7))/4 ,x= 9/4-i(3sqrt(7))/4

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2 x^{2} - 9 x + 18 = 0

x = \frac{9}{4} + i \frac{3 7}{4}, x = \frac{9}{4} - i \frac{3 7}{4}

Solution steps

2 x^{2} - 9 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 18}{2 \cdot 2}

Simplify

(- 9)^{2} - 4 \cdot 2 \cdot 18 : 37 i

x_{1, 2} = \frac{- ( - 9 ) \pm 3 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 7 i}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 3 7 i}{2 \cdot 2}

x = \frac{- ( - 9 ) + 3 7 i}{2 \cdot 2} : \frac{9}{4} + i \frac{3 7}{4}

x = \frac{- ( - 9 ) - 3 7 i}{2 \cdot 2} : \frac{9}{4} - i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = \frac{9}{4} + i \frac{3 7}{4}, x = \frac{9}{4} - i \frac{3 7}{4}

x^{2} + x = 0

x^{2} - 4 x + 34 = 0

\frac{1}{3} w^{2} + \frac{1}{3} w = - \frac{1}{4}

x^{2} - x - 6 = 9

x^{2} - 11 x - 24 = 0

What are the solutions to the equation 2x^2-9x+18=0 ?
The solutions to the equation 2x^2-9x+18=0 are x= 9/4+i(3sqrt(7))/4 ,x= 9/4-i(3sqrt(7))/4
Find the zeros of 2x^2-9x+18=0
The zeros of 2x^2-9x+18=0 are x= 9/4+i(3sqrt(7))/4 ,x= 9/4-i(3sqrt(7))/4