What are the solutions to the equation 3(x-2)^2=-6 ?

The solutions to the equation 3(x-2)^2=-6 are x=sqrt(2)i+2,x=-sqrt(2)i+2

Find the zeros of 3(x-2)^2=-6

The zeros of 3(x-2)^2=-6 are x=sqrt(2)i+2,x=-sqrt(2)i+2

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3 (x - 2)^{2} = - 6

x = 2 i + 2, x = - 2 i + 2

Solution steps

3 (x - 2)^{2} = - 6

Divide both sides by

3

(x - 2)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 2 : x = 2 i + 2

Solve

x - 2 = - - 2 : x = - 2 i + 2

The solutions to the quadratic equation are:

x = 2 i + 2, x = - 2 i + 2

8 x^{2} + (3 k - 4) x + 7 = 0

- x^{2} + 30 x - 225 = 0

r^{2} = - 1

1 - 0.9 x + 0.2 x^{2} = 0

5 x^{2} - 7 x + 6 = 10 x - 7 x^{2}

What are the solutions to the equation 3(x-2)^2=-6 ?
The solutions to the equation 3(x-2)^2=-6 are x=sqrt(2)i+2,x=-sqrt(2)i+2
Find the zeros of 3(x-2)^2=-6
The zeros of 3(x-2)^2=-6 are x=sqrt(2)i+2,x=-sqrt(2)i+2