What are the solutions to the equation 7v^2-14v+4=3 ?

The solutions to the equation 7v^2-14v+4=3 are v=(7+sqrt(42))/7 ,v=(7-sqrt(42))/7

Find the zeros of 7v^2-14v+4=3

The zeros of 7v^2-14v+4=3 are v=(7+sqrt(42))/7 ,v=(7-sqrt(42))/7

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7 v^{2} - 14 v + 4 = 3

v = \frac{7 + 42}{7}, v = \frac{7 - 42}{7}

Decimal Notation

v = 1.92582 \dots, v = 0.07417 \dots

Solution steps

7 v^{2} - 14 v + 4 = 3

Move

3

to the left side

7 v^{2} - 14 v + 1 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 7 \cdot 1}{2 \cdot 7}

(- 14)^{2} - 4 \cdot 7 \cdot 1 = 242

v_{1, 2} = \frac{- ( - 14 ) \pm 2 42}{2 \cdot 7}

Separate the solutions

v_{1} = \frac{- ( - 14 ) + 2 42}{2 \cdot 7}, v_{2} = \frac{- ( - 14 ) - 2 42}{2 \cdot 7}

v = \frac{- ( - 14 ) + 2 42}{2 \cdot 7} : \frac{7 + 42}{7}

v = \frac{- ( - 14 ) - 2 42}{2 \cdot 7} : \frac{7 - 42}{7}

The solutions to the quadratic equation are:

v = \frac{7 + 42}{7}, v = \frac{7 - 42}{7}

9 x^{2} + 30 x + 28 = 0

3 x^{2} + 15 x = 72

x^{2} - 18 x + 79 = 0

(x - 2) (x - 9) = 0

- 3 x^{2} + x = 0

What are the solutions to the equation 7v^2-14v+4=3 ?
The solutions to the equation 7v^2-14v+4=3 are v=(7+sqrt(42))/7 ,v=(7-sqrt(42))/7
Find the zeros of 7v^2-14v+4=3
The zeros of 7v^2-14v+4=3 are v=(7+sqrt(42))/7 ,v=(7-sqrt(42))/7