What are the solutions to the equation 6x^2+x-15=8 ?

The solutions to the equation 6x^2+x-15=8 are x=(-1+sqrt(553))/(12),x=(-1-sqrt(553))/(12)

Find the zeros of 6x^2+x-15=8

The zeros of 6x^2+x-15=8 are x=(-1+sqrt(553))/(12),x=(-1-sqrt(553))/(12)

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6 x^{2} + x - 15 = 8

x = \frac{- 1 + 553}{12}, x = \frac{- 1 - 553}{12}

Decimal Notation

x = 1.87632 \dots, x = - 2.04299 \dots

Solution steps

6 x^{2} + x - 15 = 8

Move

8

to the left side

6 x^{2} + x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 23 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 23) = 553

x_{1, 2} = \frac{- 1 \pm 553}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 553}{2 \cdot 6}, x_{2} = \frac{- 1 - 553}{2 \cdot 6}

x = \frac{- 1 + 553}{2 \cdot 6} : \frac{- 1 + 553}{12}

x = \frac{- 1 - 553}{2 \cdot 6} : \frac{- 1 - 553}{12}

The solutions to the quadratic equation are:

x = \frac{- 1 + 553}{12}, x = \frac{- 1 - 553}{12}

3 x^{2} + 2 x + \frac{1}{4} = 0

(x - 4)^{2} = - 81

4 x^{2} = x^{2} + 2

x, 3 x^{2} = 0

x^{2} - 16 x = 36

What are the solutions to the equation 6x^2+x-15=8 ?
The solutions to the equation 6x^2+x-15=8 are x=(-1+sqrt(553))/(12),x=(-1-sqrt(553))/(12)
Find the zeros of 6x^2+x-15=8
The zeros of 6x^2+x-15=8 are x=(-1+sqrt(553))/(12),x=(-1-sqrt(553))/(12)