What are the solutions to the equation 20x^2+13x-21=-23 ?

The solutions to the equation 20x^2+13x-21=-23 are x=-1/4 ,x=-2/5

Find the zeros of 20x^2+13x-21=-23

The zeros of 20x^2+13x-21=-23 are x=-1/4 ,x=-2/5

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20 x^{2} + 13 x - 21 = - 23

x = - \frac{1}{4}, x = - \frac{2}{5}

Decimal Notation

x = - 0.25, x = - 0.4

Solution steps

20 x^{2} + 13 x - 21 = - 23

Move

23

to the left side

20 x^{2} + 13 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 20 \cdot 2}{2 \cdot 20}

1 3^{2} - 4 \cdot 20 \cdot 2 = 3

x_{1, 2} = \frac{- 13 \pm 3}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 13 + 3}{2 \cdot 20}, x_{2} = \frac{- 13 - 3}{2 \cdot 20}

x = \frac{- 13 + 3}{2 \cdot 20} : - \frac{1}{4}

x = \frac{- 13 - 3}{2 \cdot 20} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - \frac{2}{5}

x^{2} - 16 x + 64 = 100

3 x^{2} - 9 x + 7 = 0

3 x^{2} + 5 x + 10 = 0

x, 2 (x + 2)^{2} = 72

x^{2} + 2 x - 2

What are the solutions to the equation 20x^2+13x-21=-23 ?
The solutions to the equation 20x^2+13x-21=-23 are x=-1/4 ,x=-2/5
Find the zeros of 20x^2+13x-21=-23
The zeros of 20x^2+13x-21=-23 are x=-1/4 ,x=-2/5