What are the solutions to the equation m^2+4m-12=0 ?

The solutions to the equation m^2+4m-12=0 are m=2,m=-6

Find the zeros of m^2+4m-12=0

The zeros of m^2+4m-12=0 are m=2,m=-6

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m^{2} + 4 m - 12 = 0

m = 2, m = - 6

Solution steps

m^{2} + 4 m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 12) = 8

m_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 8}{2 \cdot 1}, m_{2} = \frac{- 4 - 8}{2 \cdot 1}

m = \frac{- 4 + 8}{2 \cdot 1} : 2

m = \frac{- 4 - 8}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

m = 2, m = - 6

x - 1 = x^{2} - 14 x + 49

3 x^{2} + 18 x

x^{2} + 3 x + 2

- 3 x^{2} = 48

w^{2} - 100 = 0

What are the solutions to the equation m^2+4m-12=0 ?
The solutions to the equation m^2+4m-12=0 are m=2,m=-6
Find the zeros of m^2+4m-12=0
The zeros of m^2+4m-12=0 are m=2,m=-6