What are the solutions to the equation -2x^2-24x=0 ?

The solutions to the equation -2x^2-24x=0 are x=-12,x=0

Find the zeros of -2x^2-24x=0

The zeros of -2x^2-24x=0 are x=-12,x=0

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- 2 x^{2} - 24 x = 0

x = - 12, x = 0

Solution steps

- 2 x^{2} - 24 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

(- 24)^{2} - 4 (- 2) \cdot 0 = 24

x_{1, 2} = \frac{- ( - 24 ) \pm 24}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 24}{2 ( - 2 )}, x_{2} = \frac{- ( - 24 ) - 24}{2 ( - 2 )}

x = \frac{- ( - 24 ) + 24}{2 ( - 2 )} : - 12

x = \frac{- ( - 24 ) - 24}{2 ( - 2 )} : 0

The solutions to the quadratic equation are:

x = - 12, x = 0

(x - 5)^{2} - 100 = 0

(1 + x)^{2} + (2 + x)^{2} = (3 - x)^{2}

v, a = \frac{v ^{2}}{r}

x^{2} - 4 x = 13

x, 4 x^{2} - y^{2} = 0

What are the solutions to the equation -2x^2-24x=0 ?
The solutions to the equation -2x^2-24x=0 are x=-12,x=0
Find the zeros of -2x^2-24x=0
The zeros of -2x^2-24x=0 are x=-12,x=0