What are the solutions to the equation 5x^2+20x+20=0 ?

The solutions to the equation 5x^2+20x+20=0 are x=-2

Find the zeros of 5x^2+20x+20=0

The zeros of 5x^2+20x+20=0 are x=-2

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5 x^{2} + 20 x + 20 = 0

x = - 2

Solution steps

5 x^{2} + 20 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 \cdot 20 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 5}

x = \frac{- 20}{2 \cdot 5}

\frac{- 20}{2 \cdot 5} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

x^{2} + 2 x - 15

- 0.0241 x^{2} + x + 5.5 = 0

(x + 2)^{2} = 3 (x + 2)

x^{2} + x - \frac{1}{2} = 0

x, - 2 x^{2} y + y^{2} = 1

What are the solutions to the equation 5x^2+20x+20=0 ?
The solutions to the equation 5x^2+20x+20=0 are x=-2
Find the zeros of 5x^2+20x+20=0
The zeros of 5x^2+20x+20=0 are x=-2