What are the solutions to the equation (x-5)(40-x)=4(x-5) ?

The solutions to the equation (x-5)(40-x)=4(x-5) are x=5,x=36

Find the zeros of (x-5)(40-x)=4(x-5)

The zeros of (x-5)(40-x)=4(x-5) are x=5,x=36

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(x - 5) (40 - x) = 4 (x - 5)

x = 5, x = 36

Solution steps

(x - 5) (40 - x) = 4 (x - 5)

Move

4 (x - 5)

to the left side

(x - 5) (40 - x) - 4 (x - 5) = 0

Factor

(x - 5) (40 - x) - 4 (x - 5) : - (x - 5) (x - 36)

- (x - 5) (x - 36) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x - 36 = 0

Solve

x - 5 = 0 : x = 5

Solve

x - 36 = 0 : x = 36

The solutions to the quadratic equation are:

x = 5, x = 36

x^{2} + 6 x + 14 = (x - h) 2 + k

x^{2} = 2.8

t^{2} - t - 2 = 0

x^{2} - 6 x + 12 = - 5

\frac{5}{32} y^{2} - \frac{11}{8} y + 1 = 0

What are the solutions to the equation (x-5)(40-x)=4(x-5) ?
The solutions to the equation (x-5)(40-x)=4(x-5) are x=5,x=36
Find the zeros of (x-5)(40-x)=4(x-5)
The zeros of (x-5)(40-x)=4(x-5) are x=5,x=36