What are the solutions to the equation 7x^2-5=0 ?

The solutions to the equation 7x^2-5=0 are x=sqrt(5/7),x=-sqrt(5/7)

Find the zeros of 7x^2-5=0

The zeros of 7x^2-5=0 are x=sqrt(5/7),x=-sqrt(5/7)

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7 x^{2} - 5 = 0

x = \frac{5}{7}, x = - \frac{5}{7}

Decimal Notation

x = 0.84515 \dots, x = - 0.84515 \dots

Solution steps

7 x^{2} - 5 = 0

Move

5

to the right side

7 x^{2} = 5

Divide both sides by

7

x^{2} = \frac{5}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{7}, x = - \frac{5}{7}

x^{2} - 2 x + 1 = 80

3 a^{2} - a + 2 = 7 a

x, y = a x^{2} + b x + c

x^{2} - 16 x - 38 = 0

x^{2} + 4 x - 5

What are the solutions to the equation 7x^2-5=0 ?
The solutions to the equation 7x^2-5=0 are x=sqrt(5/7),x=-sqrt(5/7)
Find the zeros of 7x^2-5=0
The zeros of 7x^2-5=0 are x=sqrt(5/7),x=-sqrt(5/7)