What are the solutions to the equation -2x^2+4x=14 ?

The solutions to the equation -2x^2+4x=14 are x=1-sqrt(6)i,x=1+sqrt(6)i

Find the zeros of -2x^2+4x=14

The zeros of -2x^2+4x=14 are x=1-sqrt(6)i,x=1+sqrt(6)i

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- 2 x^{2} + 4 x = 14

x = 1 - 6 i, x = 1 + 6 i

Solution steps

- 2 x^{2} + 4 x = 14

Move

14

to the left side

- 2 x^{2} + 4 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( - 14 )}{2 ( - 2 )}

Simplify

4^{2} - 4 (- 2) (- 14) : 46 i

x_{1, 2} = \frac{- 4 \pm 4 6 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 6 i}{2 ( - 2 )}, x_{2} = \frac{- 4 - 4 6 i}{2 ( - 2 )}

x = \frac{- 4 + 4 6 i}{2 ( - 2 )} : 1 - 6 i

x = \frac{- 4 - 4 6 i}{2 ( - 2 )} : 1 + 6 i

The solutions to the quadratic equation are:

x = 1 - 6 i, x = 1 + 6 i

4 x^{2} + 8 x - 9 = 0

2 x^{2} = - 1

(3 x - 2)^{2} - 1 = 15

\frac{x ^{2}}{3} - \frac{1}{5} = \frac{17}{15}

81 = x^{2}

What are the solutions to the equation -2x^2+4x=14 ?
The solutions to the equation -2x^2+4x=14 are x=1-sqrt(6)i,x=1+sqrt(6)i
Find the zeros of -2x^2+4x=14
The zeros of -2x^2+4x=14 are x=1-sqrt(6)i,x=1+sqrt(6)i