What are the solutions to the equation (x+5)^2+(x+3)=5 ?

The solutions to the equation (x+5)^2+(x+3)=5 are x=(-11+sqrt(29))/2 ,x=(-11-sqrt(29))/2

Find the zeros of (x+5)^2+(x+3)=5

The zeros of (x+5)^2+(x+3)=5 are x=(-11+sqrt(29))/2 ,x=(-11-sqrt(29))/2

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(x + 5)^{2} + (x + 3) = 5

x = \frac{- 11 + 29}{2}, x = \frac{- 11 - 29}{2}

Decimal Notation

x = - 2.80741 \dots, x = - 8.19258 \dots

Solution steps

(x + 5)^{2} + (x + 3) = 5

Expand

(x + 5)^{2} + (x + 3) : x^{2} + 11 x + 28

x^{2} + 11 x + 28 = 5

Move

5

to the left side

x^{2} + 11 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 23 = 29

x_{1, 2} = \frac{- 11 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 29}{2 \cdot 1}, x_{2} = \frac{- 11 - 29}{2 \cdot 1}

x = \frac{- 11 + 29}{2 \cdot 1} : \frac{- 11 + 29}{2}

x = \frac{- 11 - 29}{2 \cdot 1} : \frac{- 11 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 29}{2}, x = \frac{- 11 - 29}{2}

5 x^{2} + 35 x = 0

2 x^{2} - 4 x = 5

ab x^{2} + (3 a + 2 b) x + 6 = 0

x, x^{2} + 10 x + y^{2} + 18 y + 110 = 0

2 x^{2} + 3 x - 18 = 0

What are the solutions to the equation (x+5)^2+(x+3)=5 ?
The solutions to the equation (x+5)^2+(x+3)=5 are x=(-11+sqrt(29))/2 ,x=(-11-sqrt(29))/2
Find the zeros of (x+5)^2+(x+3)=5
The zeros of (x+5)^2+(x+3)=5 are x=(-11+sqrt(29))/2 ,x=(-11-sqrt(29))/2