What are the solutions to the equation 5p^2=4+p ?

The solutions to the equation 5p^2=4+p are p=1,p=-4/5

Find the zeros of 5p^2=4+p

The zeros of 5p^2=4+p are p=1,p=-4/5

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5 p^{2} = 4 + p

p = 1, p = - \frac{4}{5}

Decimal Notation

p = 1, p = - 0.8

Solution steps

5 p^{2} = 4 + p

Move

p

to the left side

5 p^{2} - p = 4

Move

4

to the left side

5 p^{2} - p - 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 4) = 9

p_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 5}, p_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 5}

p = \frac{- ( - 1 ) + 9}{2 \cdot 5} : 1

p = \frac{- ( - 1 ) - 9}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

p = 1, p = - \frac{4}{5}

- 3 m^{2} + 6 m + 24 = 0

x^{2} + 7 x + 4

(x - 4)^{2} = 6

12 x^{2} - 224 x + 768 = 0

3 x^{2} + 28 x + 9 = 0

What are the solutions to the equation 5p^2=4+p ?
The solutions to the equation 5p^2=4+p are p=1,p=-4/5
Find the zeros of 5p^2=4+p
The zeros of 5p^2=4+p are p=1,p=-4/5