What are the solutions to the equation 6x^2+7x+3=0 ?

The solutions to the equation 6x^2+7x+3=0 are x=-7/12+i(sqrt(23))/(12),x=-7/12-i(sqrt(23))/(12)

Find the zeros of 6x^2+7x+3=0

The zeros of 6x^2+7x+3=0 are x=-7/12+i(sqrt(23))/(12),x=-7/12-i(sqrt(23))/(12)

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6 x^{2} + 7 x + 3 = 0

x = - \frac{7}{12} + i \frac{23}{12}, x = - \frac{7}{12} - i \frac{23}{12}

Solution steps

6 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

Simplify

7^{2} - 4 \cdot 6 \cdot 3 : 23 i

x_{1, 2} = \frac{- 7 \pm 23 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 23 i}{2 \cdot 6}, x_{2} = \frac{- 7 - 23 i}{2 \cdot 6}

x = \frac{- 7 + 23 i}{2 \cdot 6} : - \frac{7}{12} + i \frac{23}{12}

x = \frac{- 7 - 23 i}{2 \cdot 6} : - \frac{7}{12} - i \frac{23}{12}

The solutions to the quadratic equation are:

x = - \frac{7}{12} + i \frac{23}{12}, x = - \frac{7}{12} - i \frac{23}{12}

x^{2} - 7 x - 18 = 0

(v + 3) (v + 11) - 57 = - v (v + 8)

(2 x - 1) (x - 3) = 0

y, x^{3} y^{2} - x y = x + y

2 y^{2} + 3 y + 1 = 0

What are the solutions to the equation 6x^2+7x+3=0 ?
The solutions to the equation 6x^2+7x+3=0 are x=-7/12+i(sqrt(23))/(12),x=-7/12-i(sqrt(23))/(12)
Find the zeros of 6x^2+7x+3=0
The zeros of 6x^2+7x+3=0 are x=-7/12+i(sqrt(23))/(12),x=-7/12-i(sqrt(23))/(12)