What are the solutions to the equation 24x^2+8x=0 ?

The solutions to the equation 24x^2+8x=0 are x=0,x=-1/3

Find the zeros of 24x^2+8x=0

The zeros of 24x^2+8x=0 are x=0,x=-1/3

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24 x^{2} + 8 x = 0

x = 0, x = - \frac{1}{3}

Decimal Notation

x = 0, x = - 0.33333 \dots

Solution steps

24 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 24 \cdot 0}{2 \cdot 24}

8^{2} - 4 \cdot 24 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 24}, x_{2} = \frac{- 8 - 8}{2 \cdot 24}

x = \frac{- 8 + 8}{2 \cdot 24} : 0

x = \frac{- 8 - 8}{2 \cdot 24} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{3}

2 x (x - 3) = 15

v^{2} - 8 v - 33 = 0

2 x^{2} + 3 x + 2 = - 10

s^{2} + 12.91621 s + 1.25348 = 0

4 x^{2} + 8 x + 3 = 0

What are the solutions to the equation 24x^2+8x=0 ?
The solutions to the equation 24x^2+8x=0 are x=0,x=-1/3
Find the zeros of 24x^2+8x=0
The zeros of 24x^2+8x=0 are x=0,x=-1/3