What are the solutions to the equation -5t^2+50t=105 ?

The solutions to the equation -5t^2+50t=105 are t=3,t=7

Find the zeros of -5t^2+50t=105

The zeros of -5t^2+50t=105 are t=3,t=7

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- 5 t^{2} + 50 t = 105

t = 3, t = 7

Solution steps

- 5 t^{2} + 50 t = 105

Move

105

to the left side

- 5 t^{2} + 50 t - 105 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 5 ) ( - 105 )}{2 ( - 5 )}

5 0^{2} - 4 (- 5) (- 105) = 20

t_{1, 2} = \frac{- 50 \pm 20}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- 50 + 20}{2 ( - 5 )}, t_{2} = \frac{- 50 - 20}{2 ( - 5 )}

t = \frac{- 50 + 20}{2 ( - 5 )} : 3

t = \frac{- 50 - 20}{2 ( - 5 )} : 7

The solutions to the quadratic equation are:

t = 3, t = 7

x + 1 < 5

3 - x = ∣ 1 + 3 x ∣

x^{2} + 5 x + 0 = 0

x - 1 - \frac{x - 2}{2} + \frac{x - 3}{3} = 0

- 0.7 (w + 5) + 0.02 w = - 3.5

What are the solutions to the equation -5t^2+50t=105 ?
The solutions to the equation -5t^2+50t=105 are t=3,t=7
Find the zeros of -5t^2+50t=105
The zeros of -5t^2+50t=105 are t=3,t=7