What are the solutions to the equation -4x^2-530x+265=0 ?

The solutions to the equation -4x^2-530x+265=0 are x=-(265+sqrt(71285))/4 ,x=(sqrt(71285)-265)/4

Find the zeros of -4x^2-530x+265=0

The zeros of -4x^2-530x+265=0 are x=-(265+sqrt(71285))/4 ,x=(sqrt(71285)-265)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} - 530 x + 265 = 0

x = - \frac{265 + 71285}{4}, x = \frac{71285 - 265}{4}

Decimal Notation

x = - 132.99812 \dots, x = 0.49812 \dots

Solution steps

- 4 x^{2} - 530 x + 265 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 530 ) \pm ( - 530 ) ^{2} - 4 ( - 4 ) \cdot 265}{2 ( - 4 )}

(- 530)^{2} - 4 (- 4) \cdot 265 = 271285

x_{1, 2} = \frac{- ( - 530 ) \pm 2 71285}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 530 ) + 2 71285}{2 ( - 4 )}, x_{2} = \frac{- ( - 530 ) - 2 71285}{2 ( - 4 )}

x = \frac{- ( - 530 ) + 2 71285}{2 ( - 4 )} : - \frac{265 + 71285}{4}

x = \frac{- ( - 530 ) - 2 71285}{2 ( - 4 )} : \frac{71285 - 265}{4}

The solutions to the quadratic equation are:

x = - \frac{265 + 71285}{4}, x = \frac{71285 - 265}{4}

10 x^{2} + 12 x + 2 = 0

6 x^{2} - 42 x + 36 = 0

13 (x^{2} - x) = - 2 - 2 x^{2}

x (x - 2) = 143

- 2 x^{2} - 28 x = 80

What are the solutions to the equation -4x^2-530x+265=0 ?
The solutions to the equation -4x^2-530x+265=0 are x=-(265+sqrt(71285))/4 ,x=(sqrt(71285)-265)/4
Find the zeros of -4x^2-530x+265=0
The zeros of -4x^2-530x+265=0 are x=-(265+sqrt(71285))/4 ,x=(sqrt(71285)-265)/4