What are the solutions to the equation x^2-12x-20=0 ?

The solutions to the equation x^2-12x-20=0 are x=2(3+sqrt(14)),x=2(3-sqrt(14))

Find the zeros of x^2-12x-20=0

The zeros of x^2-12x-20=0 are x=2(3+sqrt(14)),x=2(3-sqrt(14))

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x^{2} - 12 x - 20 = 0

x = 2 (3 + 14), x = 2 (3 - 14)

Decimal Notation

x = 13.48331 \dots, x = - 1.48331 \dots

Solution steps

x^{2} - 12 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 20) = 414

x_{1, 2} = \frac{- ( - 12 ) \pm 4 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 14}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 14}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 14}{2 \cdot 1} : 2 (3 + 14)

x = \frac{- ( - 12 ) - 4 14}{2 \cdot 1} : 2 (3 - 14)

The solutions to the quadratic equation are:

x = 2 (3 + 14), x = 2 (3 - 14)

2 x + 3 - x^{2} = 0

x, x^{2} y - x y^{2} + y^{2} = 7

m x^{2} + (2 m - 1) x + m - 1 = 0

y, x = y^{2} - 4 y + 1

x, x^{2} + y^{2} + 5 = 0

What are the solutions to the equation x^2-12x-20=0 ?
The solutions to the equation x^2-12x-20=0 are x=2(3+sqrt(14)),x=2(3-sqrt(14))
Find the zeros of x^2-12x-20=0
The zeros of x^2-12x-20=0 are x=2(3+sqrt(14)),x=2(3-sqrt(14))