What are the solutions to the equation -2x^2+9=0 ?

The solutions to the equation -2x^2+9=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

Find the zeros of -2x^2+9=0

The zeros of -2x^2+9=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

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- 2 x^{2} + 9 = 0

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

- 2 x^{2} + 9 = 0

Move

9

to the right side

- 2 x^{2} = - 9

Divide both sides by

- 2

x^{2} = \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{2}, x = - \frac{9}{2}

\frac{9}{2} = \frac{3}{2}

- \frac{9}{2} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

4 x^{2} - 6 = 0

2 x^{2} + 2 x = 5

x^{2} - 11 x = - 24

x^{2} + 4 x - 45 = 0

u^{2} - 2 u - 24 = 0

What are the solutions to the equation -2x^2+9=0 ?
The solutions to the equation -2x^2+9=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))
Find the zeros of -2x^2+9=0
The zeros of -2x^2+9=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))