What are the solutions to the equation y^2+5y-3=0 ?

The solutions to the equation y^2+5y-3=0 are y=(-5+sqrt(37))/2 ,y=(-5-sqrt(37))/2

Find the zeros of y^2+5y-3=0

The zeros of y^2+5y-3=0 are y=(-5+sqrt(37))/2 ,y=(-5-sqrt(37))/2

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y^{2} + 5 y - 3 = 0

y = \frac{- 5 + 37}{2}, y = \frac{- 5 - 37}{2}

Decimal Notation

y = 0.54138 \dots, y = - 5.54138 \dots

Solution steps

y^{2} + 5 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 3) = 37

y_{1, 2} = \frac{- 5 \pm 37}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 37}{2 \cdot 1}, y_{2} = \frac{- 5 - 37}{2 \cdot 1}

y = \frac{- 5 + 37}{2 \cdot 1} : \frac{- 5 + 37}{2}

y = \frac{- 5 - 37}{2 \cdot 1} : \frac{- 5 - 37}{2}

The solutions to the quadratic equation are:

y = \frac{- 5 + 37}{2}, y = \frac{- 5 - 37}{2}

x^{2} + 30 x - 400 = 0

x^{2} + 42 x + 8 = 0

- 3 = 4 x^{2} + 9 x

a = s^{2}

y^{2} = - 20

What are the solutions to the equation y^2+5y-3=0 ?
The solutions to the equation y^2+5y-3=0 are y=(-5+sqrt(37))/2 ,y=(-5-sqrt(37))/2
Find the zeros of y^2+5y-3=0
The zeros of y^2+5y-3=0 are y=(-5+sqrt(37))/2 ,y=(-5-sqrt(37))/2