What are the solutions to the equation -1-3a^2=-4 ?

The solutions to the equation -1-3a^2=-4 are a=1,a=-1

Find the zeros of -1-3a^2=-4

The zeros of -1-3a^2=-4 are a=1,a=-1

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- 1 - 3 a^{2} = - 4

a = 1, a = - 1

Solution steps

- 1 - 3 a^{2} = - 4

Move

1

to the right side

- 3 a^{2} = - 3

Divide both sides by

- 3

a^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 1, a = - 1

1 = 1

- 1 = - 1

a = 1, a = - 1

4 (t + 1)^{2} = 9

x^{2} - 10 = 90

x^{2} = - x + 2

2 x^{2} + 5 = 3 x

2 x^{2} + 5 = 77

What are the solutions to the equation -1-3a^2=-4 ?
The solutions to the equation -1-3a^2=-4 are a=1,a=-1
Find the zeros of -1-3a^2=-4
The zeros of -1-3a^2=-4 are a=1,a=-1