What are the solutions to the equation x^2-5x=2(4x-11) ?

The solutions to the equation x^2-5x=2(4x-11) are x=11,x=2

Find the zeros of x^2-5x=2(4x-11)

The zeros of x^2-5x=2(4x-11) are x=11,x=2

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x^{2} - 5 x = 2 (4 x - 11)

x = 11, x = 2

Solution steps

x^{2} - 5 x = 2 (4 x - 11)

Expand

2 (4 x - 11) : 8 x - 22

x^{2} - 5 x = 8 x - 22

Move

22

to the left side

x^{2} - 5 x + 22 = 8 x

Move

8 x

to the left side

x^{2} - 13 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 22 = 9

x_{1, 2} = \frac{- ( - 13 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 9}{2 \cdot 1}

x = \frac{- ( - 13 ) + 9}{2 \cdot 1} : 11

x = \frac{- ( - 13 ) - 9}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 11, x = 2

x^{2} - 24 = 5 x

4 x^{2} - 12 x + 9

4 x^{2} - 7 = - 11

4 x^{2} + 4 x = - 17

(1 - x)^{2} - 4 = 0

What are the solutions to the equation x^2-5x=2(4x-11) ?
The solutions to the equation x^2-5x=2(4x-11) are x=11,x=2
Find the zeros of x^2-5x=2(4x-11)
The zeros of x^2-5x=2(4x-11) are x=11,x=2