What are the solutions to the equation factor 2x^2+4x-16=0 ?

The solutions to the equation factor 2x^2+4x-16=0 are x=2,x=-4

Find the zeros of factor 2x^2+4x-16=0

The zeros of factor 2x^2+4x-16=0 are x=2,x=-4

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2 x^{2} + 4 x - 16 = 0

x = 2, x = - 4

Solution steps

2 x^{2} + 4 x - 16 = 0

Factor

2 x^{2} + 4 x - 16 : 2 (x - 2) (x + 4)

2 (x - 2) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

2 x^{2} + 8 x + 26 = 0

2 x^{2} + x - 2 = 4

2 x^{2} + 20 x = - 48

3 x^{2} + 3 - 6 x = 2 (x - 1)^{2}

242 - 6 x^{2} = 0

What are the solutions to the equation factor 2x^2+4x-16=0 ?
The solutions to the equation factor 2x^2+4x-16=0 are x=2,x=-4
Find the zeros of factor 2x^2+4x-16=0
The zeros of factor 2x^2+4x-16=0 are x=2,x=-4