What are the solutions to the equation m^2-2m+m=0 ?

The solutions to the equation m^2-2m+m=0 are m=1,m=0

Find the zeros of m^2-2m+m=0

The zeros of m^2-2m+m=0 are m=1,m=0

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m^{2} - 2 m + m = 0

m = 1, m = 0

Solution steps

m^{2} - 2 m + m = 0

Refine

m^{2} - m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

m_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

m = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

m = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

m = 1, m = 0

s^{2} + 7 s + 12 = 0

9 x^{2} + 3 x = 0

- 5 x^{2} + 6 x + 8 = 0

k^{2} - 12 k + 35 = 0

x^{2} + (d + 6) x + 8 d = 0

What are the solutions to the equation m^2-2m+m=0 ?
The solutions to the equation m^2-2m+m=0 are m=1,m=0
Find the zeros of m^2-2m+m=0
The zeros of m^2-2m+m=0 are m=1,m=0