What are the solutions to the equation 3x^2-x+10=0 ?

The solutions to the equation 3x^2-x+10=0 are x= 1/6+i(sqrt(119))/6 ,x= 1/6-i(sqrt(119))/6

Find the zeros of 3x^2-x+10=0

The zeros of 3x^2-x+10=0 are x= 1/6+i(sqrt(119))/6 ,x= 1/6-i(sqrt(119))/6

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3 x^{2} - x + 10 = 0

x = \frac{1}{6} + i \frac{119}{6}, x = \frac{1}{6} - i \frac{119}{6}

Solution steps

3 x^{2} - x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

Simplify

(- 1)^{2} - 4 \cdot 3 \cdot 10 : 119 i

x_{1, 2} = \frac{- ( - 1 ) \pm 119 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 119 i}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 119 i}{2 \cdot 3}

x = \frac{- ( - 1 ) + 119 i}{2 \cdot 3} : \frac{1}{6} + i \frac{119}{6}

x = \frac{- ( - 1 ) - 119 i}{2 \cdot 3} : \frac{1}{6} - i \frac{119}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{119}{6}, x = \frac{1}{6} - i \frac{119}{6}

j (x) = (x - 3)^{2} - 4

0 = x^{2} - 7 x - 8

v^{2} - 16 v - 48 = - 4

- x^{2} + 100 x = 0

2 b^{2} + 5 b = 42

What are the solutions to the equation 3x^2-x+10=0 ?
The solutions to the equation 3x^2-x+10=0 are x= 1/6+i(sqrt(119))/6 ,x= 1/6-i(sqrt(119))/6
Find the zeros of 3x^2-x+10=0
The zeros of 3x^2-x+10=0 are x= 1/6+i(sqrt(119))/6 ,x= 1/6-i(sqrt(119))/6