What are the solutions to the equation 16x^2+36x+8=0 ?

The solutions to the equation 16x^2+36x+8=0 are x=-1/4 ,x=-2

Find the zeros of 16x^2+36x+8=0

The zeros of 16x^2+36x+8=0 are x=-1/4 ,x=-2

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16 x^{2} + 36 x + 8 = 0

x = - \frac{1}{4}, x = - 2

Decimal Notation

x = - 0.25, x = - 2

Solution steps

16 x^{2} + 36 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 16 \cdot 8}{2 \cdot 16}

3 6^{2} - 4 \cdot 16 \cdot 8 = 28

x_{1, 2} = \frac{- 36 \pm 28}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 36 + 28}{2 \cdot 16}, x_{2} = \frac{- 36 - 28}{2 \cdot 16}

x = \frac{- 36 + 28}{2 \cdot 16} : - \frac{1}{4}

x = \frac{- 36 - 28}{2 \cdot 16} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - 2

x^{2} - 2 x - 8 = 0

2 a^{2} = 72

0 = x^{2} + 2 x + 2

0 = x^{2} - 3 x - 18

3 (4 n - 1)^{2} + 1 = - 16

What are the solutions to the equation 16x^2+36x+8=0 ?
The solutions to the equation 16x^2+36x+8=0 are x=-1/4 ,x=-2
Find the zeros of 16x^2+36x+8=0
The zeros of 16x^2+36x+8=0 are x=-1/4 ,x=-2