What are the solutions to the equation 7n^2-2n-36=6n^2-11n ?

The solutions to the equation 7n^2-2n-36=6n^2-11n are n=3,n=-12

Find the zeros of 7n^2-2n-36=6n^2-11n

The zeros of 7n^2-2n-36=6n^2-11n are n=3,n=-12

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7 n^{2} - 2 n - 36 = 6 n^{2} - 11 n

n = 3, n = - 12

Solution steps

7 n^{2} - 2 n - 36 = 6 n^{2} - 11 n

Move

11 n

to the left side

7 n^{2} + 9 n - 36 = 6 n^{2}

Move

6 n^{2}

to the left side

n^{2} + 9 n - 36 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 36) = 15

n_{1, 2} = \frac{- 9 \pm 15}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 9 + 15}{2 \cdot 1}, n_{2} = \frac{- 9 - 15}{2 \cdot 1}

n = \frac{- 9 + 15}{2 \cdot 1} : 3

n = \frac{- 9 - 15}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

n = 3, n = - 12

(x + 1)^{2} + (x - 3)^{2} = 15

8 = 2 x^{2}

2 x^{2} + 10 x + 3 = 0

5^{2} = 2^{2} + x^{2}

x^{2} + 21 x - 100 = 0

What are the solutions to the equation 7n^2-2n-36=6n^2-11n ?
The solutions to the equation 7n^2-2n-36=6n^2-11n are n=3,n=-12
Find the zeros of 7n^2-2n-36=6n^2-11n
The zeros of 7n^2-2n-36=6n^2-11n are n=3,n=-12