What are the solutions to the equation solvefor x,16y^2-x^2+2x+64y+63=0 ?

The solutions to the equation solvefor x,16y^2-x^2+2x+64y+63=0 are x=-4y-7,x=4y+9

Find the zeros of solvefor x,16y^2-x^2+2x+64y+63=0

The zeros of solvefor x,16y^2-x^2+2x+64y+63=0 are x=-4y-7,x=4y+9

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solve for

x, 16 y^{2} - x^{2} + 2 x + 64 y + 63 = 0

x = - 4 y - 7, x = 4 y + 9

Solution steps

16 y^{2} - x^{2} + 2 x + 64 y + 63 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x + 16 y^{2} + 64 y + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( 16 y ^{2} + 64 y + 63 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (16 y^{2} + 64 y + 63) : 8 (y + 2)

x_{1, 2} = \frac{- 2 \pm 8 ( y + 2 )}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 8 ( y + 2 )}{2 ( - 1 )}, x_{2} = \frac{- 2 - 8 ( y + 2 )}{2 ( - 1 )}

x = \frac{- 2 + 8 ( y + 2 )}{2 ( - 1 )} : - 4 y - 7

x = \frac{- 2 - 8 ( y + 2 )}{2 ( - 1 )} : 4 y + 9

The solutions to the quadratic equation are:

x = - 4 y - 7, x = 4 y + 9

(x - 7) (x + 3) = 0

5 X^{2} + 7 X + 2 = 0

0 = 2 x^{2} + 4 x - 16

3 x^{2} + 6 x = - 3

x^{2} - 7 = 29

What are the solutions to the equation solvefor x,16y^2-x^2+2x+64y+63=0 ?
The solutions to the equation solvefor x,16y^2-x^2+2x+64y+63=0 are x=-4y-7,x=4y+9
Find the zeros of solvefor x,16y^2-x^2+2x+64y+63=0
The zeros of solvefor x,16y^2-x^2+2x+64y+63=0 are x=-4y-7,x=4y+9