What are the solutions to the equation -2=-3x^2+5x ?

The solutions to the equation -2=-3x^2+5x are x=-1/3 ,x=2

Find the zeros of -2=-3x^2+5x

The zeros of -2=-3x^2+5x are x=-1/3 ,x=2

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- 2 = - 3 x^{2} + 5 x

x = - \frac{1}{3}, x = 2

Decimal Notation

x = - 0.33333 \dots, x = 2

Solution steps

- 2 = - 3 x^{2} + 5 x

Switch sides

- 3 x^{2} + 5 x = - 2

Move

2

to the left side

- 3 x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 3 ) \cdot 2}{2 ( - 3 )}

5^{2} - 4 (- 3) \cdot 2 = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 ( - 3 )}, x_{2} = \frac{- 5 - 7}{2 ( - 3 )}

x = \frac{- 5 + 7}{2 ( - 3 )} : - \frac{1}{3}

x = \frac{- 5 - 7}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = 2

3 x^{2} - 4 x - 10 = 0

X^{2} - 49 = 0

\frac{y ^{2} - 3}{2} + \frac{y}{4} = 1

n^{2} + 15 n + 43 = 0

x^{2} = 4 x + 8

What are the solutions to the equation -2=-3x^2+5x ?
The solutions to the equation -2=-3x^2+5x are x=-1/3 ,x=2
Find the zeros of -2=-3x^2+5x
The zeros of -2=-3x^2+5x are x=-1/3 ,x=2