What are the solutions to the equation y^2-2y=15 ?

The solutions to the equation y^2-2y=15 are y=5,y=-3

Find the zeros of y^2-2y=15

The zeros of y^2-2y=15 are y=5,y=-3

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y^{2} - 2 y = 15

y = 5, y = - 3

Solution steps

y^{2} - 2 y = 15

Move

15

to the left side

y^{2} - 2 y - 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

y_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

y = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

y = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

y = 5, y = - 3

x^{2} + 4 x - 21 = 0

0 = (x - 2) (x + 4)

2 x^{2} + 24 x + 70 = 0

5 x (x + 2) = 2 x (x + 1)

x, x^{2} - 10 x + 25 = 0

What are the solutions to the equation y^2-2y=15 ?
The solutions to the equation y^2-2y=15 are y=5,y=-3
Find the zeros of y^2-2y=15
The zeros of y^2-2y=15 are y=5,y=-3