What are the solutions to the equation x^2+2=27 ?

The solutions to the equation x^2+2=27 are x=5,x=-5

Find the zeros of x^2+2=27

The zeros of x^2+2=27 are x=5,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 = 27

x = 5, x = - 5

Solution steps

x^{2} + 2 = 27

Move

2

to the right side

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

6 x^{2} - 15 x - 9 = 0

4 (x - 2) + 1 = 5 x - x (x - 3)

x, (x - 3)^{2} + (y - 2)^{2} = 0

x^{2} + x^{2} = 8^{2}

10 x^{2} - 5 = 85

What are the solutions to the equation x^2+2=27 ?
The solutions to the equation x^2+2=27 are x=5,x=-5
Find the zeros of x^2+2=27
The zeros of x^2+2=27 are x=5,x=-5