What are the solutions to the equation k^2-16=0 ?

The solutions to the equation k^2-16=0 are k=4,k=-4

Find the zeros of k^2-16=0

The zeros of k^2-16=0 are k=4,k=-4

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k^{2} - 16 = 0

k = 4, k = - 4

Solution steps

k^{2} - 16 = 0

Move

16

to the right side

k^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 16, k = - 16

16 = 4

- 16 = - 4

k = 4, k = - 4

b, A = \frac{1}{6} b^{2} c

x^{2} - 6 x + 8 = 0

y^{2} - 8 y

4 x^{2} - 4 x + 11 = 0

y, z = x^{3} + 3 x y^{2} - 15 x - 12 y

What are the solutions to the equation k^2-16=0 ?
The solutions to the equation k^2-16=0 are k=4,k=-4
Find the zeros of k^2-16=0
The zeros of k^2-16=0 are k=4,k=-4