What are the solutions to the equation 3x^2-14x+7=0 ?

The solutions to the equation 3x^2-14x+7=0 are x=(7+2sqrt(7))/3 ,x=(7-2sqrt(7))/3

Find the zeros of 3x^2-14x+7=0

The zeros of 3x^2-14x+7=0 are x=(7+2sqrt(7))/3 ,x=(7-2sqrt(7))/3

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3 x^{2} - 14 x + 7 = 0

x = \frac{7 + 2 7}{3}, x = \frac{7 - 2 7}{3}

Decimal Notation

x = 4.09716 \dots, x = 0.56949 \dots

Solution steps

3 x^{2} - 14 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 \cdot 7 = 47

x_{1, 2} = \frac{- ( - 14 ) \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4 7}{2 \cdot 3}, x_{2} = \frac{- ( - 14 ) - 4 7}{2 \cdot 3}

x = \frac{- ( - 14 ) + 4 7}{2 \cdot 3} : \frac{7 + 2 7}{3}

x = \frac{- ( - 14 ) - 4 7}{2 \cdot 3} : \frac{7 - 2 7}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 2 7}{3}, x = \frac{7 - 2 7}{3}

x, (x - 3)^{2} + 4 y - 4 x y = 0

5 x^{2} + 12 x + 6 = 0

x^{2} - 6 x + 1 = 0

u^{2} + u - 6 = 0

y^{2} + 10 y

What are the solutions to the equation 3x^2-14x+7=0 ?
The solutions to the equation 3x^2-14x+7=0 are x=(7+2sqrt(7))/3 ,x=(7-2sqrt(7))/3
Find the zeros of 3x^2-14x+7=0
The zeros of 3x^2-14x+7=0 are x=(7+2sqrt(7))/3 ,x=(7-2sqrt(7))/3