What are the solutions to the equation 24x=-48-3x^2 ?

The solutions to the equation 24x=-48-3x^2 are x=-4

Find the zeros of 24x=-48-3x^2

The zeros of 24x=-48-3x^2 are x=-4

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24 x = - 48 - 3 x^{2}

x = - 4

Solution steps

24 x = - 48 - 3 x^{2}

Switch sides

- 48 - 3 x^{2} = 24 x

Move

24 x

to the left side

- 48 - 3 x^{2} - 24 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} - 24 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 3 ) ( - 48 )}{2 ( - 3 )}

(- 24)^{2} - 4 (- 3) (- 48) = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 ( - 3 )}

x = \frac{- ( - 24 )}{2 ( - 3 )}

\frac{- ( - 24 )}{2 ( - 3 )} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

x^{2} + 9^{2} = 1 0^{2}

x^{2} - 96 = 20 x

x, x^{2} + y^{2} + 10 y + 25 = 0

x^{2} - \frac{1}{3} x + 1

(\frac{x - 7}{4})^{2} + (\frac{x - 3}{4})^{2} = \frac{169}{16}

What are the solutions to the equation 24x=-48-3x^2 ?
The solutions to the equation 24x=-48-3x^2 are x=-4
Find the zeros of 24x=-48-3x^2
The zeros of 24x=-48-3x^2 are x=-4