What are the solutions to the equation z^2+3z+2=0 ?

The solutions to the equation z^2+3z+2=0 are z=-1,z=-2

Find the zeros of z^2+3z+2=0

The zeros of z^2+3z+2=0 are z=-1,z=-2

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z^{2} + 3 z + 2 = 0

z = - 1, z = - 2

Solution steps

z^{2} + 3 z + 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

z_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 3 + 1}{2 \cdot 1}, z_{2} = \frac{- 3 - 1}{2 \cdot 1}

z = \frac{- 3 + 1}{2 \cdot 1} : - 1

z = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

z = - 1, z = - 2

19 + c^{2} = 10

7 x^{2} - 13 x = 14

7 x^{2} + 2 = 30

3 p^{2} + 7 = - 9 p^{2} + 4

- 8 x + 4 x^{2} = 6

What are the solutions to the equation z^2+3z+2=0 ?
The solutions to the equation z^2+3z+2=0 are z=-1,z=-2
Find the zeros of z^2+3z+2=0
The zeros of z^2+3z+2=0 are z=-1,z=-2