What are the solutions to the equation 2x(x-3)=5 ?

The solutions to the equation 2x(x-3)=5 are x=(3+sqrt(19))/2 ,x=(3-sqrt(19))/2

Find the zeros of 2x(x-3)=5

The zeros of 2x(x-3)=5 are x=(3+sqrt(19))/2 ,x=(3-sqrt(19))/2

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2 x (x - 3) = 5

x = \frac{3 + 19}{2}, x = \frac{3 - 19}{2}

Decimal Notation

x = 3.67944 \dots, x = - 0.67944 \dots

Solution steps

2 x (x - 3) = 5

Expand

2 x (x - 3) : 2 x^{2} - 6 x

2 x^{2} - 6 x = 5

Move

5

to the left side

2 x^{2} - 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 5) = 219

x_{1, 2} = \frac{- ( - 6 ) \pm 2 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 19}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 19}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 19}{2 \cdot 2} : \frac{3 + 19}{2}

x = \frac{- ( - 6 ) - 2 19}{2 \cdot 2} : \frac{3 - 19}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 19}{2}, x = \frac{3 - 19}{2}

x^{2} + 1 0^{2} = 1 2^{2}

- 4 x^{2} + 8 x = 0

7 x^{2} - 9 x = 0

y^{2} - 14 y

7 x^{2} + 28 x + 26

What are the solutions to the equation 2x(x-3)=5 ?
The solutions to the equation 2x(x-3)=5 are x=(3+sqrt(19))/2 ,x=(3-sqrt(19))/2
Find the zeros of 2x(x-3)=5
The zeros of 2x(x-3)=5 are x=(3+sqrt(19))/2 ,x=(3-sqrt(19))/2