What are the solutions to the equation w^2+8w+16=0 ?

The solutions to the equation w^2+8w+16=0 are w=-4

Find the zeros of w^2+8w+16=0

The zeros of w^2+8w+16=0 are w=-4

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w^{2} + 8 w + 16 = 0

w = - 4

Solution steps

w^{2} + 8 w + 16 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

w_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

w = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

w = - 4

The solution to the quadratic equation is:

w = - 4

s^{2} - 4 s + 20

6 x^{2} = 10 x - 1

x^{2} + 14 x + 49 = 9

w^{2} = 100

4 x^{2} = - 8 x

What are the solutions to the equation w^2+8w+16=0 ?
The solutions to the equation w^2+8w+16=0 are w=-4
Find the zeros of w^2+8w+16=0
The zeros of w^2+8w+16=0 are w=-4