What are the solutions to the equation x^2-4x-72=0 ?

The solutions to the equation x^2-4x-72=0 are x=2(1+sqrt(19)),x=2(1-sqrt(19))

Find the zeros of x^2-4x-72=0

The zeros of x^2-4x-72=0 are x=2(1+sqrt(19)),x=2(1-sqrt(19))

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x^{2} - 4 x - 72 = 0

x = 2 (1 + 19), x = 2 (1 - 19)

Decimal Notation

x = 10.71779 \dots, x = - 6.71779 \dots

Solution steps

x^{2} - 4 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 72) = 419

x_{1, 2} = \frac{- ( - 4 ) \pm 4 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 19}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 19}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 19}{2 \cdot 1} : 2 (1 + 19)

x = \frac{- ( - 4 ) - 4 19}{2 \cdot 1} : 2 (1 - 19)

The solutions to the quadratic equation are:

x = 2 (1 + 19), x = 2 (1 - 19)

x^{2} = \frac{x + 3}{2}

a^{2} = a 5

x, 2 x^{2} + 2 y^{2} + 4 x + 2 y + 10 = 0

3 x^{2} - 6 x = 0

- 6 x - 2 = (3 x + 1)^{2}

What are the solutions to the equation x^2-4x-72=0 ?
The solutions to the equation x^2-4x-72=0 are x=2(1+sqrt(19)),x=2(1-sqrt(19))
Find the zeros of x^2-4x-72=0
The zeros of x^2-4x-72=0 are x=2(1+sqrt(19)),x=2(1-sqrt(19))