What are the solutions to the equation 3(x+5)^2-12x=6x+138 ?

The solutions to the equation 3(x+5)^2-12x=6x+138 are x=3,x=-7

Find the zeros of 3(x+5)^2-12x=6x+138

The zeros of 3(x+5)^2-12x=6x+138 are x=3,x=-7

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3 (x + 5)^{2} - 12 x = 6 x + 138

x = 3, x = - 7

Solution steps

3 (x + 5)^{2} - 12 x = 6 x + 138

Expand

3 (x + 5)^{2} - 12 x : 3 x^{2} + 18 x + 75

3 x^{2} + 18 x + 75 = 6 x + 138

Move

138

to the left side

3 x^{2} + 18 x - 63 = 6 x

Move

6 x

to the left side

3 x^{2} + 12 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 63 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 63) = 30

x_{1, 2} = \frac{- 12 \pm 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 30}{2 \cdot 3}, x_{2} = \frac{- 12 - 30}{2 \cdot 3}

x = \frac{- 12 + 30}{2 \cdot 3} : 3

x = \frac{- 12 - 30}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

1 0^{3} x^{2} + 4 x = 2

9 x^{2} + 4 x - 1 = 0

3 x^{2} = x

x^{2} - 9 x + 27 = 0

5 m^{2} + m = 0

What are the solutions to the equation 3(x+5)^2-12x=6x+138 ?
The solutions to the equation 3(x+5)^2-12x=6x+138 are x=3,x=-7
Find the zeros of 3(x+5)^2-12x=6x+138
The zeros of 3(x+5)^2-12x=6x+138 are x=3,x=-7