What are the solutions to the equation 5n^2-20n+6=0 ?

The solutions to the equation 5n^2-20n+6=0 are n=(10+sqrt(70))/5 ,n=(10-sqrt(70))/5

Find the zeros of 5n^2-20n+6=0

The zeros of 5n^2-20n+6=0 are n=(10+sqrt(70))/5 ,n=(10-sqrt(70))/5

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5 n^{2} - 20 n + 6 = 0

n = \frac{10 + 70}{5}, n = \frac{10 - 70}{5}

Decimal Notation

n = 3.67332 \dots, n = 0.32667 \dots

Solution steps

5 n^{2} - 20 n + 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 6 = 270

n_{1, 2} = \frac{- ( - 20 ) \pm 2 70}{2 \cdot 5}

Separate the solutions

n_{1} = \frac{- ( - 20 ) + 2 70}{2 \cdot 5}, n_{2} = \frac{- ( - 20 ) - 2 70}{2 \cdot 5}

n = \frac{- ( - 20 ) + 2 70}{2 \cdot 5} : \frac{10 + 70}{5}

n = \frac{- ( - 20 ) - 2 70}{2 \cdot 5} : \frac{10 - 70}{5}

The solutions to the quadratic equation are:

n = \frac{10 + 70}{5}, n = \frac{10 - 70}{5}

x, x^{2} - y^{3} = 0

s^{2} + 8 s + 20 = 0

2500 = - 0.5 x^{2} + 40 x - 300

x, (x + y)^{2} = 1

u^{2} - 4 u + 1 = 0

What are the solutions to the equation 5n^2-20n+6=0 ?
The solutions to the equation 5n^2-20n+6=0 are n=(10+sqrt(70))/5 ,n=(10-sqrt(70))/5
Find the zeros of 5n^2-20n+6=0
The zeros of 5n^2-20n+6=0 are n=(10+sqrt(70))/5 ,n=(10-sqrt(70))/5