What are the solutions to the equation 3x^2-42x=-120 ?

The solutions to the equation 3x^2-42x=-120 are x=10,x=4

Find the zeros of 3x^2-42x=-120

The zeros of 3x^2-42x=-120 are x=10,x=4

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3 x^{2} - 42 x = - 120

x = 10, x = 4

Solution steps

3 x^{2} - 42 x = - 120

Move

120

to the left side

3 x^{2} - 42 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 3 \cdot 120}{2 \cdot 3}

(- 42)^{2} - 4 \cdot 3 \cdot 120 = 18

x_{1, 2} = \frac{- ( - 42 ) \pm 18}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 42 ) + 18}{2 \cdot 3}, x_{2} = \frac{- ( - 42 ) - 18}{2 \cdot 3}

x = \frac{- ( - 42 ) + 18}{2 \cdot 3} : 10

x = \frac{- ( - 42 ) - 18}{2 \cdot 3} : 4

The solutions to the quadratic equation are:

x = 10, x = 4

x^{2} - 2 x - 19 = 0

x^{2} + x^{2} = 4

2 x^{2} - x - 3 = 0

c, a^{2} = b^{2} + c^{2}

5 b^{2} + 12 b = 0

What are the solutions to the equation 3x^2-42x=-120 ?
The solutions to the equation 3x^2-42x=-120 are x=10,x=4
Find the zeros of 3x^2-42x=-120
The zeros of 3x^2-42x=-120 are x=10,x=4