What are the solutions to the equation (2x-5)(2x-3)/2 =0 ?

The solutions to the equation (2x-5)(2x-3)/2 =0 are x= 5/2 ,x= 3/2

Find the zeros of (2x-5)(2x-3)/2 =0

The zeros of (2x-5)(2x-3)/2 =0 are x= 5/2 ,x= 3/2

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(2 x - 5) \frac{2 x - 3}{2} = 0

x = \frac{5}{2}, x = \frac{3}{2}

Decimal Notation

x = 2.5, x = 1.5

Solution steps

(2 x - 5) \frac{2 x - 3}{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or \frac{2 x - 3}{2} = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

\frac{2 x - 3}{2} = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = \frac{3}{2}

k (x) = 4 x^{2} + 1, k (- 3)

- x^{2} = 8 x + 1

(x - 8) (x + 8) = 0

- 4.9 t^{2} + 30 t = 0

z^{2} - 4 z + 13 = 0

What are the solutions to the equation (2x-5)(2x-3)/2 =0 ?
The solutions to the equation (2x-5)(2x-3)/2 =0 are x= 5/2 ,x= 3/2
Find the zeros of (2x-5)(2x-3)/2 =0
The zeros of (2x-5)(2x-3)/2 =0 are x= 5/2 ,x= 3/2