What are the solutions to the equation 9x^2+42x+52=0 ?

The solutions to the equation 9x^2+42x+52=0 are x=-7/3+i(sqrt(3))/3 ,x=-7/3-i(sqrt(3))/3

Find the zeros of 9x^2+42x+52=0

The zeros of 9x^2+42x+52=0 are x=-7/3+i(sqrt(3))/3 ,x=-7/3-i(sqrt(3))/3

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9 x^{2} + 42 x + 52 = 0

x = - \frac{7}{3} + i \frac{3}{3}, x = - \frac{7}{3} - i \frac{3}{3}

Solution steps

9 x^{2} + 42 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 9 \cdot 52}{2 \cdot 9}

Simplify

4 2^{2} - 4 \cdot 9 \cdot 52 : 63 i

x_{1, 2} = \frac{- 42 \pm 6 3 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 42 + 6 3 i}{2 \cdot 9}, x_{2} = \frac{- 42 - 6 3 i}{2 \cdot 9}

x = \frac{- 42 + 6 3 i}{2 \cdot 9} : - \frac{7}{3} + i \frac{3}{3}

x = \frac{- 42 - 6 3 i}{2 \cdot 9} : - \frac{7}{3} - i \frac{3}{3}

The solutions to the quadratic equation are:

x = - \frac{7}{3} + i \frac{3}{3}, x = - \frac{7}{3} - i \frac{3}{3}

2 x^{2} - 14 = - 12 x

x^{2} + 12 x + 16 = 0

y^{2} - 2 = 0

x, f = x^{2} y + y^{2} z

2 x^{2} - 12 x - 18 = 0

What are the solutions to the equation 9x^2+42x+52=0 ?
The solutions to the equation 9x^2+42x+52=0 are x=-7/3+i(sqrt(3))/3 ,x=-7/3-i(sqrt(3))/3
Find the zeros of 9x^2+42x+52=0
The zeros of 9x^2+42x+52=0 are x=-7/3+i(sqrt(3))/3 ,x=-7/3-i(sqrt(3))/3