What are the solutions to the equation 8x=5+5x^2 ?

The solutions to the equation 8x=5+5x^2 are x= 4/5+i 3/5 ,x= 4/5-i 3/5

Find the zeros of 8x=5+5x^2

The zeros of 8x=5+5x^2 are x= 4/5+i 3/5 ,x= 4/5-i 3/5

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8 x = 5 + 5 x^{2}

x = \frac{4}{5} + i \frac{3}{5}, x = \frac{4}{5} - i \frac{3}{5}

Solution steps

8 x = 5 + 5 x^{2}

Switch sides

5 + 5 x^{2} = 8 x

Move

8 x

to the left side

5 + 5 x^{2} - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 8 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

(- 8)^{2} - 4 \cdot 5 \cdot 5 : 6 i

x_{1, 2} = \frac{- ( - 8 ) \pm 6 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 6 i}{2 \cdot 5}, x_{2} = \frac{- ( - 8 ) - 6 i}{2 \cdot 5}

x = \frac{- ( - 8 ) + 6 i}{2 \cdot 5} : \frac{4}{5} + i \frac{3}{5}

x = \frac{- ( - 8 ) - 6 i}{2 \cdot 5} : \frac{4}{5} - i \frac{3}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5} + i \frac{3}{5}, x = \frac{4}{5} - i \frac{3}{5}

(\frac{3}{5})^{5}

(x - 8) (x - 12) > 0

lo g_{3} (\frac{1}{9})

\frac{1}{2} x + \frac{1}{3} = \frac{3}{4} x - \frac{1}{5}

x^{2} - 16 x + 3 = 0

What are the solutions to the equation 8x=5+5x^2 ?
The solutions to the equation 8x=5+5x^2 are x= 4/5+i 3/5 ,x= 4/5-i 3/5
Find the zeros of 8x=5+5x^2
The zeros of 8x=5+5x^2 are x= 4/5+i 3/5 ,x= 4/5-i 3/5