What are the solutions to the equation (x+1)/2+(10x^2+3x)/8 =(x^2)/4+5/8 ?

The solutions to the equation (x+1)/2+(10x^2+3x)/8 =(x^2)/4+5/8 are x= 1/8 ,x=-1

Find the zeros of (x+1)/2+(10x^2+3x)/8 =(x^2)/4+5/8

The zeros of (x+1)/2+(10x^2+3x)/8 =(x^2)/4+5/8 are x= 1/8 ,x=-1

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\frac{x + 1}{2} + \frac{10 x ^{2} + 3 x}{8} = \frac{x ^{2}}{4} + \frac{5}{8}

x = \frac{1}{8}, x = - 1

Decimal Notation

x = 0.125, x = - 1

Solution steps

\frac{x + 1}{2} + \frac{10 x ^{2} + 3 x}{8} = \frac{x ^{2}}{4} + \frac{5}{8}

Find Least Common Multiplier of

2, 8, 4 : 8

Multiply by LCM=

8

\frac{x + 1}{2} \cdot 8 + \frac{10 x ^{2} + 3 x}{8} \cdot 8 = \frac{x ^{2}}{4} \cdot 8 + \frac{5}{8} \cdot 8

Simplify

4 (x + 1) + 10 x^{2} + 3 x = 2 x^{2} + 5

Expand

4 (x + 1) + 10 x^{2} + 3 x : 10 x^{2} + 7 x + 4

10 x^{2} + 7 x + 4 = 2 x^{2} + 5

Move

5

to the left side

10 x^{2} + 7 x - 1 = 2 x^{2}

Move

2 x^{2}

to the left side

8 x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

7^{2} - 4 \cdot 8 (- 1) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 8}, x_{2} = \frac{- 7 - 9}{2 \cdot 8}

x = \frac{- 7 + 9}{2 \cdot 8} : \frac{1}{8}

x = \frac{- 7 - 9}{2 \cdot 8} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{8}, x = - 1

z^{2} + 4 z + 5 = 0

11 x^{2} - x = 0

x^{2} - 7 x + 12 = 0

x (x + 2) + 5 = 4

x^{2} + x + 11 = 0

What are the solutions to the equation (x+1)/2+(10x^2+3x)/8 =(x^2)/4+5/8 ?
The solutions to the equation (x+1)/2+(10x^2+3x)/8 =(x^2)/4+5/8 are x= 1/8 ,x=-1
Find the zeros of (x+1)/2+(10x^2+3x)/8 =(x^2)/4+5/8
The zeros of (x+1)/2+(10x^2+3x)/8 =(x^2)/4+5/8 are x= 1/8 ,x=-1