What are the solutions to the equation -8b^2-3b+22=0 ?

The solutions to the equation -8b^2-3b+22=0 are b=-(3+sqrt(713))/(16),b=(sqrt(713)-3)/(16)

Find the zeros of -8b^2-3b+22=0

The zeros of -8b^2-3b+22=0 are b=-(3+sqrt(713))/(16),b=(sqrt(713)-3)/(16)

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- 8 b^{2} - 3 b + 22 = 0

b = - \frac{3 + 713}{16}, b = \frac{713 - 3}{16}

Decimal Notation

b = - 1.85637 \dots, b = 1.48137 \dots

Solution steps

- 8 b^{2} - 3 b + 22 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 8 ) \cdot 22}{2 ( - 8 )}

(- 3)^{2} - 4 (- 8) \cdot 22 = 713

b_{1, 2} = \frac{- ( - 3 ) \pm 713}{2 ( - 8 )}

Separate the solutions

b_{1} = \frac{- ( - 3 ) + 713}{2 ( - 8 )}, b_{2} = \frac{- ( - 3 ) - 713}{2 ( - 8 )}

b = \frac{- ( - 3 ) + 713}{2 ( - 8 )} : - \frac{3 + 713}{16}

b = \frac{- ( - 3 ) - 713}{2 ( - 8 )} : \frac{713 - 3}{16}

The solutions to the quadratic equation are:

b = - \frac{3 + 713}{16}, b = \frac{713 - 3}{16}

(m + 1) (4 m - 10) = 3 (m + 4) - 9

2 x^{2} - 12 x - 54 = 0

x^{2} + 3 x + 5

x^{2} + 12 x + 41 = 0

3 x^{2} + 10 x = 0

What are the solutions to the equation -8b^2-3b+22=0 ?
The solutions to the equation -8b^2-3b+22=0 are b=-(3+sqrt(713))/(16),b=(sqrt(713)-3)/(16)
Find the zeros of -8b^2-3b+22=0
The zeros of -8b^2-3b+22=0 are b=-(3+sqrt(713))/(16),b=(sqrt(713)-3)/(16)