What are the solutions to the equation -2x^2-4=-8x ?

The solutions to the equation -2x^2-4=-8x are x=2-sqrt(2),x=2+sqrt(2)

Find the zeros of -2x^2-4=-8x

The zeros of -2x^2-4=-8x are x=2-sqrt(2),x=2+sqrt(2)

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- 2 x^{2} - 4 = - 8 x

x = 2 - 2, x = 2 + 2

Decimal Notation

x = 0.58578 \dots, x = 3.41421 \dots

Solution steps

- 2 x^{2} - 4 = - 8 x

Move

8 x

to the left side

- 2 x^{2} - 4 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 4) = 42

x_{1, 2} = \frac{- 8 \pm 4 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 2}{2 ( - 2 )}, x_{2} = \frac{- 8 - 4 2}{2 ( - 2 )}

x = \frac{- 8 + 4 2}{2 ( - 2 )} : 2 - 2

x = \frac{- 8 - 4 2}{2 ( - 2 )} : 2 + 2

The solutions to the quadratic equation are:

x = 2 - 2, x = 2 + 2

9 x^{2} - 12 x + 4 = 0

0 = 3 x^{2} - 2

7 x^{2} + 4 = 0

49 x^{2} = 28 x - 5

10 x^{2} - 6 x + 4 = - 3 x

What are the solutions to the equation -2x^2-4=-8x ?
The solutions to the equation -2x^2-4=-8x are x=2-sqrt(2),x=2+sqrt(2)
Find the zeros of -2x^2-4=-8x
The zeros of -2x^2-4=-8x are x=2-sqrt(2),x=2+sqrt(2)