What are the solutions to the equation x^2+30x+225=0 ?

The solutions to the equation x^2+30x+225=0 are x=-15

Find the zeros of x^2+30x+225=0

The zeros of x^2+30x+225=0 are x=-15

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x^{2} + 30 x + 225 = 0

x = - 15

Solution steps

x^{2} + 30 x + 225 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 1 \cdot 225}{2 \cdot 1}

3 0^{2} - 4 \cdot 1 \cdot 225 = 0

x_{1, 2} = \frac{- 30 \pm 0}{2 \cdot 1}

x = \frac{- 30}{2 \cdot 1}

\frac{- 30}{2 \cdot 1} = - 15

x = - 15

The solution to the quadratic equation is:

x = - 15

- 3 x^{2} + 12 x + 2 = 0

x^{2} + 7 x + 30 = 0

p^{2} - 37 p = 0

0 = (x + 1) (x - 3)

(2 x - 3)^{2} - 2 (2 x - 3) - 8 = 0

What are the solutions to the equation x^2+30x+225=0 ?
The solutions to the equation x^2+30x+225=0 are x=-15
Find the zeros of x^2+30x+225=0
The zeros of x^2+30x+225=0 are x=-15